[AMRadio] Erratum |
Donald Chester
k4kyv at charter.net
Tue Dec 17 17:25:49 EST 2013
My posting of Mon 16-Dec-13 14:59 titled "Re: Trouble brewing ..." contains the following error: <<For parity in talk power, you would need the same total sideband power for both modes. 1500 watts of peak sideband power for AM translates to 3000 watts of fully modulated carrier power, since only on voice PEAKS does the modulation hit 100%... ***P = voltage squared X R.*** Doubling the voltage by vectorally combining the two sidebands gives twice the voltage or 4 times the power of each sideband taken individually...<< The power formula stated above should have read: P = Voltage squared / R. Power is proportional to the square of the voltage. Therefore, doubling the signal voltage at the detector output is the effect of a four-fold increase in sideband power. Sorry if this caused any confusion. Don --- This email is free from viruses and malware because avast! Antivirus protection is active. http://www.avast.com
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